1/5(3x^2-10)=12

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Solution for 1/5(3x^2-10)=12 equation: 


x in (-oo:+oo)

(1/5)*(3*x^2-10) = 12 // - 12

(1/5)*(3*x^2-10)-12 = 0

1/5*(3*x^2-10)-12 = 0

1/5*(3*x^2-10)-12 = 0

3/5*x^2-14 = 0

3/5*x^2-14 = 0

3/5*x^2 = 14 // : 3/5

x^2 = 70/3

x^2 = 70/3 // ^ 1/2

abs(x) = (70/3)^(1/2)

x = (70/3)^(1/2) or x = -(70/3)^(1/2)

x in { (70/3)^(1/2), -(70/3)^(1/2) }

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